Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:35Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 11 9 ; 0 12 | = 132
52K
∇²α = 0
det| 11 5 ; 0 12 | = 132
91K
det| 5 6 ; 5 6 | = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
50K
∑_{k=1}^{n} k = n(n+1)/2
det| 4 6 ; 4 5 | = -4
137K
det| 9 4 ; 1 10 | = 86
197K
d/dn [n^5] = 5n^4
∫₀^∞ e^(-β²) dβ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2