Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:09Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
102K
∫₀^∞ e^(-n²) dn = √π / 2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∇ × E = −∂B/∂t
λ = h/p
det| 11 2 ; 5 12 | = 122
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1