Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:26Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-t²) dt = √π / 2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 7 4 ; 4 8 | = 40
50K
det| 8 3 ; 4 9 | = 60
∫₀^∞ e^(-y²) dy = √π / 2
137K
det| 3 3 ; 4 4 | = 0
197K
9x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
∑_{k=1}^{n} k = n(n+1)/2
196K