Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:01Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 11 5 ; 0 12 | = 132
100K
det| 8 3 ; 4 9 | = 60
det| 9 4 ; 1 10 | = 86
197K
∑_{k=1}^{n} k = n(n+1)/2
262K