Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:41Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
52K
∇²α = 0
∫₀^∞ e^(-n²) dn = √π / 2
91K
det| 5 6 ; 5 6 | = 0
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-x²) dx = √π / 2
137K
d/dn [n^5] = 5n^4
∑_{k=1}^{n} k = n(n+1)/2
262K
det| 9 4 ; 1 10 | = 86
196K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
218K
λ = h/p
det| 7 5 ; 0 8 | = 56
det| 6 8 ; 4 7 | = 10