Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:03Z
11z² + 7z + 1 = 0
λ = h/p
det| 3 6 ; 6 4 | = -24
det| 8 2 ; 7 9 | = 58
264K
∑_{k=1}^{n} k = n(n+1)/2
276K
ΔS ≥ 0
CH₄ + 2O₂ → CO₂ + 2H₂O
250K
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
62K
F = G m₁m₂ / r²
\oint_C \vec{F}\cdot d\vec{r} = 0
6z² + 3z + 0 = 0