Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:06Z
11z² + 7z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
8K
λ = h/p
CH₄ + 2O₂ → CO₂ + 2H₂O
57K
det| 3 6 ; 6 4 | = -24
∫₀^∞ e^(-φ²) dφ = √π / 2
276K
ΔS ≥ 0
CH₄ + 2O₂ → CO₂ + 2H₂O
257K
∇²γ = 0