Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:47Z
∇²γ = 0
6t² + 5t + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
N₂ + 3H₂ ⇌ 2NH₃
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
10φ² + 3φ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
196K
∑_{k=1}^{n} k = n(n+1)/2
299K