Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:21Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
244K
det| 9 4 ; 1 10 | = 86
52K
det| 12 5 ; 4 13 | = 136
det| 1 2 ; 7 2 | = -12
90K
∑_{k=1}^{n} k = n(n+1)/2
91K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 9 ; 5 10 | = 45
262K