Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:07Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 5 6 ; 5 6 | = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
50K
∑_{k=1}^{n} k = n(n+1)/2
d/dn [n^5] = 5n^4
∑_{k=1}^{n} k = n(n+1)/2
262K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 9 4 ; 1 10 | = 86
299K
det| 7 5 ; 0 8 | = 56
det| 6 8 ; 4 7 | = 10