Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:22Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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E = mc²
det| 3 3 ; 4 4 | = 0
102K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 1 4 ; 2 2 | = -6
276K
∇ × E = −∂B/∂t
det| 7 4 ; 4 8 | = 40
250K
λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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∑_{k=1}^{n} k = n(n+1)/2
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\oint_C \vec{F}\cdot d\vec{r} = 0
46K