Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:16Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
479K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8K
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
102K
det| 7 4 ; 4 8 | = 40
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
264K
∇ × E = −∂B/∂t
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
250K
∑_{k=1}^{n} k = n(n+1)/2
46K