Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:33Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
102K
∑_{k=1}^{n} k = n(n+1)/2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-x²) dx = √π / 2
264K
\oint_C \vec{F}\cdot d\vec{r} = 0
276K
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
257K
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1