Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:05Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
52K
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
9x² + 3x + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
196K
9ψ² + 3ψ + 3 = 0
det| 9 4 ; 1 10 | = 86
299K