Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 18:12Z
F = G m₁m₂ / r²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
479K
e^{i\pi} + 1 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
264K
det| 7 4 ; 4 8 | = 40
276K
8β² + 7β + 7 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
257K
\frac{9}{4} \sum_{i=1}^{n} i^{2}
\lim_{n\to 0} \frac{\sin n}{n} = 1
\frac{12}{6} \sum_{i=1}^{n} i^{2}
46K
1ψ² + 9ψ + 4 = 0