Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 06:01Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
∫₀^∞ e^(-y²) dy = √π / 2
8K
det| 5 9 ; 4 6 | = -6
F = G m₁m₂ / r²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
276K
9ω² + 3ω + 5 = 0
det| 7 4 ; 4 8 | = 40
250K
9θ² + 8θ + 7 = 0
det| 1 2 ; 7 2 | = -12
256K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
46K