Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:01Z
∑_{k=1}^{n} k = n(n+1)/2
det| 12 5 ; 4 13 | = 136
∫₀^∞ e^(-ω²) dω = √π / 2
90K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 4 9 ; 7 5 | = -43
∑_{k=1}^{n} k = n(n+1)/2
137K
∑_{k=1}^{n} k = n(n+1)/2
197K
det| 1 1 ; 3 2 | = -1
det| 12 9 ; 5 13 | = 111
262K
det| 8 5 ; 3 9 | = 57
196K
det| 9 4 ; 1 10 | = 86
218K