Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:17Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-t²) dt = √π / 2
244K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
52K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 9 4 ; 1 10 | = 86
197K
d/dz [z^11] = 11z^10
262K
∫₀^∞ e^(-t²) dt = √π / 2
196K
∑_{k=1}^{n} k = n(n+1)/2
218K
det| 4 8 ; 3 5 | = -4
299K