Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:42Z
8θ² + 4θ + 7 = 0
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 5 6 ; 5 6 | = 0
det| 7 4 ; 4 8 | = 40
50K
∑_{k=1}^{n} k = n(n+1)/2
d/dn [n^5] = 5n^4
∑_{k=1}^{n} k = n(n+1)/2
262K
CH₄ + 2O₂ → CO₂ + 2H₂O
196K
∑_{k=1}^{n} k = n(n+1)/2
299K