Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 19:15Z
det| 2 5 ; 0 3 | = 6
AgNO₃ + NaCl → AgCl↓ + NaNO₃
244K
E = mc²
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
90K
9β² + 8β + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
100K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\oint_C \vec{F}\cdot d\vec{r} = 0
137K
\oint_C \vec{F}\cdot d\vec{r} = 0
262K