Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:15Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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E = mc²
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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\oint_C \vec{F}\cdot d\vec{r} = 0
∇ × E = −∂B/∂t
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
257K
\lim_{t\to 0} \frac{\sin t}{t} = 1
250K
λ = h/p
det| 2 4 ; 4 3 | = -10
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂