Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:17Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∑_{k=1}^{n} k = n(n+1)/2
479K
E = mc²
\frac{11}{6} \sum_{i=1}^{n} i^{2}
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\oint_C \vec{F}\cdot d\vec{r} = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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∇ × E = −∂B/∂t
det| 7 4 ; 4 8 | = 40
250K
λ = h/p
\frac{8}{6} \sum_{i=1}^{n} i^{2}
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂