Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:06Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
det| 7 4 ; 4 8 | = 40
137K
det| 3 3 ; 4 4 | = 0
197K
9x² + 3x + 6 = 0
9ψ² + 3ψ + 3 = 0