Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:36Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
264K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
276K
∇ × E = −∂B/∂t
λ = h/p
det| 7 4 ; 4 8 | = 40
62K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 2 7 ; 7 3 | = -43
46K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
164K