Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:02Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
52K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 7 7 ; 4 8 | = 28
100K
det| 9 4 ; 1 10 | = 86
50K
det| 5 3 ; 2 6 | = 24
137K
∑_{k=1}^{n} k = n(n+1)/2
197K