Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∫₀^∞ e^(-n²) dn = √π / 2
8K
E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
257K
CH₄ + 2O₂ → CO₂ + 2H₂O
250K
λ = h/p
∫₀^∞ e^(-θ²) dθ = √π / 2
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 4 ; 4 8 | = 40
46K
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1