Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:38Z
8θ² + 4θ + 7 = 0
∇²α = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
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∑_{k=1}^{n} k = n(n+1)/2
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det| 5 6 ; 5 6 | = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
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d/dn [n^5] = 5n^4
∫₀^∞ e^(-β²) dβ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2