Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:36Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8K
E = mc²
det| 4 6 ; 4 5 | = -4
102K
∫₀^∞ e^(-α²) dα = √π / 2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∇ × E = −∂B/∂t
CH₄ + 2O₂ → CO₂ + 2H₂O
250K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1