Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:25Z
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
6t² + 5t + 2 = 0
N₂ + 3H₂ ⇌ 2NH₃
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
det| 9 4 ; 1 10 | = 86
137K
10φ² + 3φ + 2 = 0
det| 11 1 ; 1 12 | = 131
∑_{k=1}^{n} k = n(n+1)/2
218K
3φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf