Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:36Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
det| 4 6 ; 4 5 | = -4
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 2 7 ; 7 3 | = -43
50K
det| 8 3 ; 4 9 | = 60
∫₀^∞ e^(-n²) dn = √π / 2
137K
9x² + 3x + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
262K
∫₀^∞ e^(-ω²) dω = √π / 2
196K
CH₄ + 2O₂ → CO₂ + 2H₂O
218K