Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 00:27Z
11y² + 4y + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
8K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
102K
∫₀^∞ e^(-n²) dn = √π / 2
57K
det| 12 1 ; 0 13 | = 156
CaCO₃ → CaO + CO₂
∑_{k=1}^{n} k = n(n+1)/2
257K
E = mc²
det| 9 9 ; 5 10 | = 45
62K
det| 9 4 ; 1 10 | = 86
256K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 10 3 ; 4 11 | = 98
46K
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
11θ² + 5θ + 3 = 0