Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:12Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 9 4 ; 1 10 | = 86
52K
det| 2 2 ; 6 3 | = -6
∑_{k=1}^{n} k = n(n+1)/2
91K
d/dφ [φ^6] = 6φ^5
det| 7 7 ; 4 8 | = 28
100K
∑_{k=1}^{n} k = n(n+1)/2
50K
det| 10 3 ; 1 11 | = 107
det| 11 7 ; 4 12 | = 104
∑_{k=1}^{n} k = n(n+1)/2
262K
∑_{k=1}^{n} k = n(n+1)/2
196K