Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:20Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
52K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 2 7 ; 7 3 | = -43
100K
det| 8 3 ; 4 9 | = 60
d/dz [z^11] = 11z^10
137K
9x² + 3x + 6 = 0
det| 5 3 ; 2 6 | = 24
218K