Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:38Z
8θ² + 4θ + 7 = 0
∇²α = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
det| 5 6 ; 5 6 | = 0
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
137K
det| 9 4 ; 1 10 | = 86
197K
d/dn [n^5] = 5n^4
∑_{k=1}^{n} k = n(n+1)/2