Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:07Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
264K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
276K
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
250K
λ = h/p
d/dθ [θ^7] = 7θ^6
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂