Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:26Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
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CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
262K
det| 7 4 ; 4 8 | = 40
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