Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 21:48Z
4ω² + 7ω + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
∑_{k=1}^{n} k = n(n+1)/2
8K
F = ma
11t² + 5t + 7 = 0
det| 9 6 ; 0 10 | = 90
264K
∑_{k=1}^{n} k = n(n+1)/2
62K
det| 7 4 ; 4 8 | = 40
256K