Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:32Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
102K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-α²) dα = √π / 2
264K
∇ × E = −∂B/∂t
\frac{8}{6} \sum_{i=1}^{n} i^{2}
250K
λ = h/p
d/dθ [θ^7] = 7θ^6
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂