Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-18 21:27Z
iħ ∂ψ/∂t = Ĥψ
\frac{11}{5} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-n²) dn = √π / 2
268K
2H₂ + O₂ → 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
121K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
7K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
21K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-φ²) dφ = √π / 2