Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:23Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 2 2 ; 6 3 | = -6
d/dφ [φ^6] = 6φ^5
det| 9 4 ; 1 10 | = 86
50K
det| 5 3 ; 2 6 | = 24
137K
∑_{k=1}^{n} k = n(n+1)/2
197K
∫₀^∞ e^(-φ²) dφ = √π / 2
262K