Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:15Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-t²) dt = √π / 2
276K
∇ × E = −∂B/∂t
λ = h/p
∫₀^∞ e^(-α²) dα = √π / 2
62K
∑_{k=1}^{n} k = n(n+1)/2
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
46K