Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:24Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
∫₀^∞ e^(-t²) dt = √π / 2
52K
6ω² + 3ω + 2 = 0
det| 2 7 ; 7 3 | = -43
90K
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 5 6 ; 4 6 | = 6
100K
det| 8 3 ; 4 9 | = 60
det| 7 4 ; 4 8 | = 40
197K
9x² + 3x + 6 = 0
det| 10 5 ; 4 11 | = 90
196K