Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 00:35Z
11y² + 4y + 6 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
57K
det| 12 1 ; 0 13 | = 156
∫₀^∞ e^(-α²) dα = √π / 2
264K
CaCO₃ → CaO + CO₂
E = mc²
d/dz [z^11] = 11z^10
164K