Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:57Z
11z² + 7z + 1 = 0
λ = h/p
d/dz [z^11] = 11z^10
102K
det| 3 6 ; 6 4 | = -24
∑_{k=1}^{n} k = n(n+1)/2
264K
ΔS ≥ 0
det| 7 4 ; 4 8 | = 40
257K
∫₀^∞ e^(-n²) dn = √π / 2
250K
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
256K
det| 5 3 ; 2 6 | = 24
164K