Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:32Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
102K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
264K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
276K
∇ × E = −∂B/∂t
det| 9 4 ; 1 10 | = 86
257K
λ = h/p
d/dθ [θ^7] = 7θ^6
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1