Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:52Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 7 4 ; 4 8 | = 40
52K
det| 2 2 ; 6 3 | = -6
d/dφ [φ^6] = 6φ^5
∫₀^∞ e^(-y²) dy = √π / 2
50K
det| 10 3 ; 1 11 | = 107
det| 12 9 ; 5 13 | = 111
197K
∑_{k=1}^{n} k = n(n+1)/2
196K