Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:51Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-α²) dα = √π / 2
100K
det| 8 3 ; 4 9 | = 60
∑_{k=1}^{n} k = n(n+1)/2
137K
det| 5 6 ; 1 6 | = 24
196K
∑_{k=1}^{n} k = n(n+1)/2
218K