Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:39Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
\frac{11}{6} \sum_{i=1}^{n} i^{2}
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
264K
∫₀^∞ e^(-n²) dn = √π / 2
276K
∇ × E = −∂B/∂t
∫₀^∞ e^(-y²) dy = √π / 2
250K
λ = h/p
\lim_{t\to 0} \frac{\sin t}{t} = 1
62K
det| 12 9 ; 5 13 | = 111
46K