Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 06:21Z
det| 8 1 ; 6 9 | = 66
det| 7 4 ; 4 8 | = 40
244K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
90K
1n² + 9n + 0 = 0
F = ma
∑_{k=1}^{n} k = n(n+1)/2
137K
d/dω [ω^6] = 6ω^5
∑_{k=1}^{n} k = n(n+1)/2
262K
∫₀^∞ e^(-n²) dn = √π / 2