Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:58Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-α²) dα = √π / 2
52K
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
∑_{k=1}^{n} k = n(n+1)/2
137K
det| 3 3 ; 4 4 | = 0
197K
9x² + 3x + 6 = 0
d/dz [z^11] = 11z^10
262K
det| 10 7 ; 3 11 | = 89
196K